document.write( "Question 6219: The area of a rectangular piece of concrete is 120 square feet, and its perimeter is 46 feet. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #3319 by minerva(22)\"\" \"About 
You can put this solution on YOUR website!
well,this is an easy one but requres concentration.\r
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\n" ); document.write( "\n" ); document.write( " heres my solution.
\n" ); document.write( " statements:-
\n" ); document.write( " 2(l+b)=46 (perimeter)
\n" ); document.write( " (l+b)=46/2
\n" ); document.write( " l+b=23\r
\n" ); document.write( "\n" ); document.write( " therfore l=23-b
\n" ); document.write( " SUBSTITTUTING THE VALUES:-\r
\n" ); document.write( "\n" ); document.write( "area=l X b=12\r
\n" ); document.write( "\n" ); document.write( " bX (23-b)=120
\n" ); document.write( " 23b -b^2=120
\n" ); document.write( " -(b^2 -23b +120)=0\r
\n" ); document.write( "\n" ); document.write( " minus gets cancelled when diuvide d by 0\r
\n" ); document.write( "\n" ); document.write( " so, b^2 -23b +120=0
\n" ); document.write( " b^2 -15b-8b+120=0\r
\n" ); document.write( "\n" ); document.write( " b(b-15)-8(b-15)=0
\n" ); document.write( " b = 15 or b=8\r
\n" ); document.write( "\n" ); document.write( " then.... l=23-b
\n" ); document.write( " (a) 23-15=8 or (b)23-8=15\r
\n" ); document.write( "\n" ); document.write( " solution b is correct as length is always grteater than breadth
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