document.write( "Question 49923: Graph: y = 2x^2 - 4x \n" ); document.write( "

Algebra.Com's Answer #33189 by rapaljer(4671) $\"\"$ $\"About$

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The vertex for y = ax^2 + bx +c will always be at $\"x=%28-b%29%2F%282a%29+\"$ \r
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\n" ); document.write( "\n" ); document.write( "In this case a=2 and b = -4, so vertex is at $\"x=4%2F%282%2A2%29=1\"$ \r
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\n" ); document.write( "\n" ); document.write( "If x = 1, then find the y coordinate by substituting x= 1 into the equation for y, y = 2*1^2 - 4*1 = -2. \r
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\n" ); document.write( "\n" ); document.write( "This is a parabola that opens upward with vertex at (1,-2). It should look like this:
\n" ); document.write( " $\"graph+%28300%2C300%2C-6%2C6%2C-6%2C6%2C+2x%5E2-4x%29+\"$ \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "

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