document.write( "Question 49942: Im stuck.
\n" ); document.write( "8(3a-5)-4(2a+3)=12
\n" ); document.write( "Can you plz help me
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Algebra.Com's Answer #33186 by rapaljer(4671)\"\" \"About 
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Watch out for the negative in front of the 4 on this problem. This is the most likely place to make an error:\r
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\n" ); document.write( "\n" ); document.write( "Remove parentheses by distributive property:
\n" ); document.write( "8(3a-5)-4(2a+3)=12\r
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\n" ); document.write( "\n" ); document.write( "24a -40 -8a - 12 = 12
\n" ); document.write( "Combine like terms on the left side:
\n" ); document.write( "16a- 52 = 12\r
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\n" ); document.write( "\n" ); document.write( "Add +52 to each side:
\n" ); document.write( "16a - 52+52 = 12 + 52
\n" ); document.write( "16a=64
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 16.
\n" ); document.write( "a=4\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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