document.write( "Question 49942: Im stuck.
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document.write( "8(3a-5)-4(2a+3)=12
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document.write( "Can you plz help me \n" );
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Algebra.Com's Answer #33186 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Watch out for the negative in front of the 4 on this problem. This is the most likely place to make an error:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remove parentheses by distributive property: \n" ); document.write( "8(3a-5)-4(2a+3)=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "24a -40 -8a - 12 = 12 \n" ); document.write( "Combine like terms on the left side: \n" ); document.write( "16a- 52 = 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add +52 to each side: \n" ); document.write( "16a - 52+52 = 12 + 52 \n" ); document.write( "16a=64 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Divide both sides by 16. \n" ); document.write( "a=4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |