document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485197>Question 485197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angles X and Y are complementary. If mX = a – 12 and mY = a + 8, find the measure of mX. Please help me, I am doing pre-algebra and my teacher is very strict. This is yesterday's \"problem of the day\" and almost everybody got it. \r<BR>\n" );
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document.write( "Is the answer 70? Please respond with haste. \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331859 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a-12)+(a+8)=90\r<BR>\n" );
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document.write( "2a-4=90<BR>\n" );
document.write( "2a= 94<BR>\n" );
document.write( "a=47\r<BR>\n" );
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document.write( "m X = a-12==> 47-12= 35\r<BR>\n" );
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document.write( "mY= a+8==> 47+8=55\r<BR>\n" );
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