document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483933>Question 483933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me find the inverse of the following function?\r<BR>\n" );
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document.write( "f(x) = sqrt(3)(x-1) + 2\r<BR>\n" );
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document.write( "This is what I have.  Is it correct?\r<BR>\n" );
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document.write( "y-2 = sqrt(3)(x-1)<BR>\n" );
document.write( "(y-2)sqrt(3) = x-1<BR>\n" );
document.write( "(y-2)(y-2)(y-2) = x-1<BR>\n" );
document.write( "(y^2-2y-2y+4)(y-2) = x-1<BR>\n" );
document.write( "y^3-2y^2+4y^2-8y+4y-8 = x-1<BR>\n" );
document.write( "y^3+2y^2-6y-8 = x-1<BR>\n" );
document.write( "y^3+2y^2-6y-7 = x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331831 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Could you please help me find the inverse of the following function? <BR>\n" );
document.write( "f(x) = sqrt(3)(x-1) + 2 <BR>\n" );
document.write( "This is what I have. Is it correct? <BR>\n" );
document.write( "y-2 = sqrt(3)(x-1)<BR>\n" );
document.write( "(y-2)sqrt(3) = x-1<BR>\n" );
document.write( "(y-2)(y-2)(y-2) = x-1<BR>\n" );
document.write( "(y^2-2y-2y+4)(y-2) = x-1<BR>\n" );
document.write( "y^3-2y^2+4y^2-8y+4y-8 = x-1<BR>\n" );
document.write( "y^3+2y^2-6y-8 = x-1<BR>\n" );
document.write( "y^3+2y^2-6y-7 = x<BR>\n" );
document.write( "***<BR>\n" );
document.write( "To find the inverse of a function, interchange x and y, then solve for y. In effect you are solving for x in terms of y.<BR>\n" );
document.write( "f(x)=sqrt(3)(x-1) + 2<BR>\n" );
document.write( "y=sqrt(3)(x-1) + 2<BR>\n" );
document.write( "x=&#8730;3(y-1)+2<BR>\n" );
document.write( "x-2=&#8730;3(y-1)<BR>\n" );
document.write( "y-1=(x-2)/&#8730;3<BR>\n" );
document.write( "y=((x-2)/&#8730;3)+1 (inverse of f(x)) </SPAN>\n" );
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