document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485015>Question 485015</A>: <I><SPAN STYLE=\"word-break: break-all;\">  How do I find the slope of y= -2x +5. How do I find the value of x at which the 2 lines y=2x+1 and y= -1/4x + 3 intersect. I am completely confused, please if someone can show me step by step to get a solution to both of these. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331825 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slope =m<BR>\n" );
document.write( "y=mx+b<BR>\n" );
document.write( "slope m=-2<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "y=2x+1<BR>\n" );
document.write( "y=-1/4x+3<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "2x+1=-1/4x+3<BR>\n" );
document.write( "2x+1/4x=2<BR>\n" );
document.write( "2 1/4x=2<BR>\n" );
document.write( "x=2/(2 1/4)<BR>\n" );
document.write( "x=2*4/9<BR>\n" );
document.write( "x=8/9<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "y=2(8/9)+1<BR>\n" );
document.write( "y=16/9+1<BR>\n" );
document.write( "y=25/9<BR>\n" );
document.write( "y=2 7/9<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "(8/9,0)<BR>\n" );
document.write( "(0,2 7/9)<BR>\n" );
document.write( "-------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );