document.write( "Question 484739: Four times the supplement of angle A exceeds 8 times the complement of angle A by 28. Find the measure of angle A. \n" ); document.write( "
Algebra.Com's Answer #331789 by ankor@dixie-net.com(22740)\"\" \"About 
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Four times the supplement of angle A exceeds 8 times the complement of angle A by 28.
\n" ); document.write( " Find the measure of angle A.
\n" ); document.write( ":
\n" ); document.write( "We know:
\n" ); document.write( "(180-A) = the supplement of Angle A
\n" ); document.write( "and
\n" ); document.write( "(90-A) = the complement of Angle A
\n" ); document.write( ":
\n" ); document.write( "We can write the equation like this:
\n" ); document.write( "4(180-A) - 8(90-A) = 28
\n" ); document.write( "720 - 4A - 720 + 8A = 28
\n" ); document.write( "therefore
\n" ); document.write( "4A = 28
\n" ); document.write( "A = 28/4
\n" ); document.write( "A = 7 degrees
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works:
\n" ); document.write( "180-7 = 173 is the supplement
\n" ); document.write( "90 - 7 = 83 is the complement
\n" ); document.write( "\"Four times the supplement of angle A exceeds 8 times the complement of angle A by 28.\"
\n" ); document.write( "4(173) - 8(83) =
\n" ); document.write( "692 - 664 = 28!!
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