document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49918>Question 49918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplifying a product of radical expressions.\r<BR>\n" );
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document.write( "(2 square root of 3-3 square root of 10) (6 square root 10-3 square root of 3)<BR>\n" );
document.write( "3x+3x+9xyz=z </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33176 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am going to use the notation \"rt\" for \"square root of\", so the problem is (2rt3-3rt10)(6rt10-3rt3).  Now, we use the FOIL method, or any method of multiplying binomials.  If it is confusing for you to use radicals, you can pretend the rt3 and rt10 are variables, like x and y.  So you get 12rt3rt10 - 6rt3rt3 - 18rt10rt10 + 9rt10rt3.  rt3rt10 = rt10rt3 = rt30, rt3rt3=3, and rt10rt10=10, so we get 12rt30-18-180+9rt30, so the final answer is 21rt30-198. </SPAN>\n" );
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