document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484922>Question 484922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+4y=-10<BR>\n" );
document.write( "-3x-2y=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331728 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, double the second equation\r<BR>\n" );
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document.write( "2x+4y=-10<BR>\n" );
document.write( "-3x-2y=-1\r<BR>\n" );
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document.write( "2x+4y=-10<BR>\n" );
document.write( "-6x-4y=-2\r<BR>\n" );
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document.write( "Then add the two equations to get   -4x=-12\r<BR>\n" );
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document.write( "Solve for x to get   x = 3\r<BR>\n" );
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document.write( "Then plug that into either equation and solve for y\r<BR>\n" );
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document.write( "2x+4y=-10\r<BR>\n" );
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document.write( "2(3)+4y=-10\r<BR>\n" );
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document.write( "6+4y=-10\r<BR>\n" );
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document.write( "4y=-10-6\r<BR>\n" );
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document.write( "4y=-16\r<BR>\n" );
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document.write( "y=-4\r<BR>\n" );
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document.write( "Answers are x = 3 and y = -4\r<BR>\n" );
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