document.write( "Question 484870: Says to find the domain?????\r
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document.write( "f(x)= sqrt (x+1) \n" );
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Algebra.Com's Answer #331693 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You cannot take the square root of a negative number. So the radicand x+1 must be 0 or positive.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the domain is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: the above says that the domain is the set of all real numbers that are greater than or equal to -1.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In interval notation, the domain is [ |