document.write( "Question 484858: the lead car in a race is .5 miles ahead of the second ar and is traveling 2 mies per hour faster after x mohours will the lead car is d(x) miles in front of the second car where d(x) =\r
\n" ); document.write( "\n" ); document.write( "a.)(2x) - 5
\n" ); document.write( "b.) 2x + 5
\n" ); document.write( "c.)(2x).5
\n" ); document.write( "d.) 2x + .5
\n" ); document.write( "

Algebra.Com's Answer #331691 by htmentor(1343)\"\" \"About 
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the lead car in a race is .5 miles ahead of the second ar and is traveling 2 mies per hour faster after x mohours will the lead car is d(x) miles in front of the second car where d(x) =\r
\n" ); document.write( "\n" ); document.write( "a.)(2x) - 5
\n" ); document.write( "b.) 2x + 5
\n" ); document.write( "c.)(2x).5
\n" ); document.write( "d.) 2x + .5
\n" ); document.write( "=============================================
\n" ); document.write( "The initial separation is 0.5 miles at x=0 hours.
\n" ); document.write( "For every hour, the lead car will gain 2 more miles on the second car.
\n" ); document.write( "After x hours, the separation will be:
\n" ); document.write( "d(x) = 2x + 0.5
\n" ); document.write( "So the answer is d).
\n" ); document.write( "
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