document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49916>Question 49916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I determine whether the point (-2, -2) lies on the line 2x + 3y = 10? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33169 by </B><A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><B>mathchemprofessor(65)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a given point satisfies the given equation of a line, then the point lies on the line. Otherwise, it is not.<BR>\n" );
document.write( "Now, substitute the point (-2,-2) in 2x+3y=10, we get,<BR>\n" );
document.write( "2(-2)+3(-2) =-4-6=-10&#8800;10.<BR>\n" );
document.write( "Note:&#8800;means not equal to.<BR>\n" );
document.write( "So, the point (-2,-2) does not lie on the line 2x+3y=10 </SPAN>\n" );
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