document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484692>Question 484692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I write a proof for the problem (4a+3)-3a= a+ 3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331591 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite LHS as (4a + 3) + (-3a) then using the fact that addition is associative, you can say the LHS is equal to (4a - 3a) + 3 = a + 3, same as RHS. That's if you want to prove they're equal.\r<BR>\n" );
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document.write( "In reality though, we just say (4a + 3) - 3a is equal to a + 3 right off the back. </SPAN>\n" );
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