document.write( "Question 484565: The given equation involves a power of the variable. Find all real solutions of the equation. (If there is no real solution, enter NO REAL SOLUTION.)
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document.write( "8x2/3 − 200 = 0\r
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document.write( "Solve the equation for the indicated variable.
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document.write( "V = 1/3πr2h;for r \r
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Algebra.Com's Answer #331560 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 8x^(2/3) − 200 = 0 \n" ); document.write( "--- \n" ); document.write( "x^(2/3) = 25 \n" ); document.write( "--- \n" ); document.write( "x = 25^(3/2) \n" ); document.write( "--- \n" ); document.write( "x = 5^3 \n" ); document.write( "x = 125 \n" ); document.write( "=========================================== \n" ); document.write( "Solve the equation for the indicated variable. \n" ); document.write( "V = (1/3)πr2h ; for r \n" ); document.write( "--- \n" ); document.write( "(pi)r^2h = 3V \n" ); document.write( "---- \n" ); document.write( "r^2 = (3V)/[(pi)h] \n" ); document.write( "---- \n" ); document.write( "r = sqrt[(3V)/(pi*h)] \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==============\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |