document.write( "Question 484518: A plane leaves chicago and flies 750 miles to new york. if it takes 2.5 hours to get back to new york flying against the wind, but only 2 hours to fly back to chicago, what is the planes rate of speed and what is the wind speed? \n" ); document.write( "
Algebra.Com's Answer #331519 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance equals rate times time, or better for our purposes, rate equals distance divided by time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the rate of the aircraft MINUS the wind speed is equal to 750 miles divided by 2.5 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The rate of the aircraft PLUS the wind speed is equal to 750 miles divided by 2 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the system for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |