document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484441>Question 484441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a linear equation, I'm not sure if I'm in the right section, but here is what I am having trouble with:\r<BR>\n" );
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document.write( "n-3/2n-2 = 1/5 - n-5/8n-8\r<BR>\n" );
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document.write( "I thought I would try using the LCD, and I got the LCD to be 40(n-1). My answer that I got for that was 27/17, but I was informed that that was wrong.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331463 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n-3/2n-2 = 1/5 - n-5/8n-8<BR>\n" );
document.write( "I assume () are implied as<BR>\n" );
document.write( "(n-3)/(2n-2) = .2 - (n-5)/(8n-8)<BR>\n" );
document.write( "*8: (4n-12)/(n-1) = 1.6 - (n-5)/(n-1)<BR>\n" );
document.write( "(4n-12 + n-5)/(n-1) = 1.6<BR>\n" );
document.write( "(5n-17) = 1.6(n-1) if n isn't 1 (that linear assumption helps)<BR>\n" );
document.write( "3.4n = 15.4<BR>\n" );
document.write( "*5: 17n=77<BR>\n" );
document.write( "n=77/17\r<BR>\n" );
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