document.write( "Question 484418: Simplify by removing factors of 1.\r
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document.write( "The simplified form is ____ \n" );
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Algebra.Com's Answer #331460 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "yイ - 1\r\n" ); document.write( "覧覧覧予r\n" ); document.write( " 1 - y\r\n" ); document.write( "\r\n" ); document.write( "First let's arrange the denominator \r\n" ); document.write( "\r\n" ); document.write( " 1 - y\r\n" ); document.write( "\r\n" ); document.write( "in descending order:\r\n" ); document.write( "\r\n" ); document.write( "-y + 1\r\n" ); document.write( "\r\n" ); document.write( "Foctor out -1\r\n" ); document.write( "\r\n" ); document.write( "-1(y - 1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now we have \r\n" ); document.write( "\r\n" ); document.write( " yイ - 1\r\n" ); document.write( "覧覧覧覧予r\n" ); document.write( "-1(y - 1)\r\n" ); document.write( "\r\n" ); document.write( "Factor the numerator, the difference of two squares \r\n" ); document.write( "\r\n" ); document.write( "(y - 1)(y + 1)\r\n" ); document.write( "覧覧覧覧覧覧覧\r\n" ); document.write( "-1(y - 1)\r\n" ); document.write( "\r\n" ); document.write( "Now when we remove the factor of 1, also called \"cancelling\r\n" ); document.write( "the y-1's\", we get:\r\n" ); document.write( "\r\n" ); document.write( "(y + 1)\r\n" ); document.write( "覧覧覧予r\n" ); document.write( " -1\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( "-(y + 1)\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( "-y - 1\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |