document.write( "Question 484238: 1. Find two consecutive positive numbers such that the product of the sum and difference of the numbers plus 8 is the sum of their squares.\r
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Algebra.Com's Answer #331447 by ankor@dixie-net.com(22740)\"\" \"About 
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Find two consecutive positive numbers
\n" ); document.write( "x, (x+2)
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\n" ); document.write( "such that the product of the sum and difference of the numbers plus 8 is the sum of their squares.
\n" ); document.write( "(x+(x+2))*(2) + 8 = x^2 + (x+2)^2
\n" ); document.write( "(2x + 2) * 2 + 8 = x^2 + x^2 + 4x + 4
\n" ); document.write( "4x + 4 + 8 = 2x^2 + 4x + 4
\n" ); document.write( "4x + 12 = 2x^2 + 4x + 4
\n" ); document.write( "0 = 2x^2 + 4x - 4x + 4 - 12
\n" ); document.write( "2x^2 - 8 = 0
\n" ); document.write( "2x^2 = 8
\n" ); document.write( "x^2 = 8/2
\n" ); document.write( "x^2 = 4
\n" ); document.write( "x = 2 and 4 are the consecutive numbers
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\n" ); document.write( "see if that works in the statement
\n" ); document.write( "\"the product of the sum and difference of the numbers plus 8 is the sum of their squares. \"
\n" ); document.write( "(4+2)*(4-2) + 8 = 2^2 + 4^2
\n" ); document.write( "6(2) + 8 = 4 + 16
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