document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484345>Question 484345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me: the triangles hypotenuse is r and the other short sides are x and y. solve for the third side of the triangle if x= 2 sqrt ( 5 ) and r= sqrt ( 38 ). Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331398 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the triangles hypotenuse is r and the other short sides are x and y. solve for the third side of the triangle if x= 2 sqrt ( 5 ) and r= sqrt ( 38 ).<BR>\n" );
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document.write( "Using Pythagoras:<BR>\n" );
document.write( "r^2 = x^2 + y^2<BR>\n" );
document.write( "38 = 4*5 + y^2<BR>\n" );
document.write( "y^2 = -7<BR>\n" );
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document.write( "That would make y a complex number.<BR>\n" );
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document.write( "Conclusion: No Real Number solution.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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