document.write( "Question 484245: In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one. \n" ); document.write( "
Algebra.Com's Answer #331357 by Tatiana_Stebko(1539)\"\" \"About 
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P(no more than 1 defective one)=P(0 defective)+P(1 defective)
\n" ); document.write( "11 CD players, 2 defective, \"11-2=9\" not defective
\n" ); document.write( "P(0 defective)=\"%289C3%29%2F%2811C3%29\"
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\n" ); document.write( "P(0 defective)=\"%289C3%29%2F%2811C3%29=84%2F165=28%2F55\"
\n" ); document.write( "P(1 defective)=\"%289C2%2A2C1%29%2F%2811C3%29\"
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\n" ); document.write( "\"2C1=2\"
\n" ); document.write( "P(1 defective)=\"%2836%2A2%29%2F165=24%2F55\"
\n" ); document.write( "P(no more than 1 defective one)=P(0 defective)+P(1 defective)=\"28%2F55%2B24%2F55=52%2F55=0.945\"
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