document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484179>Question 484179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this equation: The measure of two complementary angles are 16z-9 and 4z+3. Find the measures of the angles.\r<BR>\n" );
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document.write( "please explain to me how you got the answer.<BR>\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331283 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First one has to know what \"complementary\" means, which (if degrees are used instead of radians) is X + Y = 90.<BR>\n" );
document.write( "Subtitute to get 16z-9 + 4z+3 = 90<BR>\n" );
document.write( "Add like terms (powers of z) to get 20z - 6 = 90<BR>\n" );
document.write( "Both +6: 20z = 96<BR>\n" );
document.write( "Both /20: z = 96/20 = 24/5<BR>\n" );
document.write( "Sub this for z in the 2 angle expressions:<BR>\n" );
document.write( "16(24/5)-9 = (386-45)/5 = 339/5 = 67.8<BR>\n" );
document.write( "4(24/5)+3 = (96+15)/5 = 111/5 = 22.2<BR>\n" );
document.write( "Important double check: these add to 90.<BR>\n" );
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