document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484170>Question 484170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 3/2x-4=-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331280 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note the typo of 2 \"=\" in the original.<BR>\n" );
document.write( "The goal is to get everything hanging around the x on the left hand side over to the right hand side via legal operations applied to both sides.<BR>\n" );
document.write( "Add 4 to both sides:<BR>\n" );
document.write( "3/2 x = -5<BR>\n" );
document.write( "(I had to show the extra step in 9th grade, but not now.  You should be able to figure that part out if required).<BR>\n" );
document.write( "Multiply both sides by 2/3:<BR>\n" );
document.write( "x = -5 * (2/3) = - (10/3)<BR>\n" );
document.write( "Or -3 1/3 if improper fractions are frowned on.<BR>\n" );
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