document.write( "Question 484137: Find the slope of a line to the line that passes through the following points.
\n" ); document.write( "1-(4,0) and (3.8,2)\r
\n" ); document.write( "\n" ); document.write( "Find the slope of a line perpendicular to the line that passes through the following points.
\n" ); document.write( "(3,9) and (7,15) \n" ); document.write( "
Algebra.Com's Answer #331278 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "4 0 3.8 2
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 2 - 0 )/( 3.8 - 4 )
\n" ); document.write( "( 2 / -0.2 )
\n" ); document.write( "m= -10 \r
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\n" ); document.write( "\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "3 9 7 15
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 15 - 9 )/( 7 - 3 )
\n" ); document.write( "( 6 / 4 )
\n" ); document.write( "m= 3/ 2
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\n" ); document.write( "Plug value of the slope and point( 3 , 9 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "9.00 = 9/2 + b
\n" ); document.write( "b= 9 - 9/2
\n" ); document.write( "b= 9/ 2
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = 3/2 x + 9/2 \r
\n" ); document.write( "\n" ); document.write( "The slope of line perpendicular to the above line will be -2/3
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