document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484041>Question 484041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean Theorem to find the distance between X(7,11) and Y(-1,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331275 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean Theorem to find the distance between X(7,11) and Y(-1,5)\r<BR>\n" );
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document.write( "Let the third coordinate point of the right triangle be W.\r<BR>\n" );
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document.write( "If diagram is drawn, it’ll be seen that in order to get W (the third x-coordinate point of the right triangle), we simply subtract the smaller of the two x-coordinates from the larger. In this case, 7 – (- 1), or 7 + 1 = 8. We do the same for the y-coordinate, as follows: 11 – 5 = 6. \r<BR>\n" );
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document.write( "This means that YW (horizontal line that’s parallel to the x-axis) has a length of 8, and XW (the vertical line that’s parallel to the y-axis) has a length of 6. \r<BR>\n" );
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document.write( "With this, we can now find YX using the Pythagorean theorem. Therefore, we can say that:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28YW%29%5E2+%2B+%28XW%29%5E2+=+%28XY%29%5E2 ALIGN=MIDDLE  ALT=\"%28YW%29%5E2+%2B+%28XW%29%5E2+=+%28XY%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%5E2+%2B+6%5E2+=+%28XY%29%5E2 ALIGN=MIDDLE  ALT=\"8%5E2+%2B+6%5E2+=+%28XY%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=64+%2B+36+=+%28XY%29%5E2 ALIGN=MIDDLE  ALT=\"64+%2B+36+=+%28XY%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100+=+%28XY%29%5E2 ALIGN=MIDDLE  ALT=\"100+=+%28XY%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28100%29+=+XY ALIGN=MIDDLE  ALT=\"sqrt%28100%29+=+XY\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "10 = XY\r<BR>\n" );
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document.write( "Therefore, distance = XY = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2810%29 ALIGN=MIDDLE  ALT=\"highlight_green%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > units\r<BR>\n" );
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document.write( "---------<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "---------\r<BR>\n" );
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document.write( "The distance formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, can be used to verify the correctness of this answer. \r<BR>\n" );
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document.write( "Send comments and “thank-yous” to MathMadEzy@aol.com </SPAN>\n" );
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