document.write( "Question 484140: Substitution Method\r
\n" ); document.write( "\n" ); document.write( "4m+n=11
\n" ); document.write( "m-8n=77 \n" ); document.write( "
Algebra.Com's Answer #331270 by mananth(16946)\"\" \"About 
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4 x + 1 y = 11 .............1
\n" ); document.write( "-8 y = 77 -1 x ---------2
\n" ); document.write( "/ -8 =
\n" ); document.write( " y = -9.63 + 0.13 x
\n" ); document.write( "Substitute y in (1)
\n" ); document.write( "4 x + 1 ( -9.63 + 0.13 x ) = 11
\n" ); document.write( "4 x -9.63 + 0.13 x = 11
\n" ); document.write( "4 x + 0.13 x = 11 9.63
\n" ); document.write( "4.13 x = 20.63
\n" ); document.write( "/ 4.13
\n" ); document.write( "x= 5
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "4 x + 1 y = 11
\n" ); document.write( "4 * 5 + 1 y = 11
\n" ); document.write( "20 + 1 y = 11
\n" ); document.write( "1 y = -9
\n" ); document.write( "/ 1
\n" ); document.write( "y= -9
\n" ); document.write( "m.ananth@hotmail.ca
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