document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=484126>Question 484126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 104 inches. The length exceeds the width by 14 inches.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331241 by </B><A HREF=/tutors/aboutme.mpl?userid=tm.hodgson><B>tm.hodgson(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tm.hodgson><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2l + 2w<BR>\n" );
document.write( "104=2(w+14)+2w<BR>\n" );
document.write( "104=2w + 28 + 2w<BR>\n" );
document.write( "104-28=4w<BR>\n" );
document.write( "76=4w<BR>\n" );
document.write( "19=w\r<BR>\n" );
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document.write( "104=2l +2(19)<BR>\n" );
document.write( "104=2l +38<BR>\n" );
document.write( "104-38=2l<BR>\n" );
document.write( "66=2l<BR>\n" );
document.write( "33=l </SPAN>\n" );
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