document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=480045>Question 480045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PQRS is a rectangle in which PQ=9 cm and PS=6cm.T is a point on PQ such that PT=7cm and RV is a perpendicular from R to ST . Calculate ST and RV?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331206 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, I made a triangle with the sides PS = 6cm and PT = 7 cm.<BR>\n" );
document.write( "PSQ is a right traingle, as the angle SPQ is the corner of a rectangle.<BR>\n" );
document.write( " This is in the left upper corner of the rectangle, and  we find the hypotenuse, ST by 6^2 + 7^2 = x^2.<BR>\n" );
document.write( "This works out to 9.2 cm, the size of ST, the first segment we are looking for.<BR>\n" );
document.write( "With this we can find the angle PST with the sine function. sin 7/9.2 = 7.60, 49.5 degrees.<BR>\n" );
document.write( "We now need to find RV which is one of the legs on triangle SVR.<BR>\n" );
document.write( "We can find angle VSR, since we know PSV to be 49.5, and we know angle PSR is 90 degrees, as it is a corner in a rectangle.<BR>\n" );
document.write( "So, 90 - 49.5 = 40.5, the measure of angle VSR. <BR>\n" );
document.write( "Again, we can use the sine function, sine of 40.5 = opp/hyp = x/9.<BR>\n" );
document.write( "0.649 * 9 = 5.85 cm. This is the size of RV.<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
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