document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483997>Question 483997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"Solve each system by substitution.\"<BR>\n" );
document.write( "y=-4x+16<BR>\n" );
document.write( "y=2x+4\r<BR>\n" );
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document.write( "I changed y=-4x+16 to -4x+y=16 then I put the bottom equation (y=2x+4) into that so:<BR>\n" );
document.write( "-4x+(2x+4)=16 and got x=-6 so I put that into y=2x+4 so y=2(6)+4 and got y=16 but I don't think it's right. (-6,16) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331198 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-4x+16\r<BR>\n" );
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document.write( "2x+4 =-4x+16\r<BR>\n" );
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document.write( "2x+4x =16-4\r<BR>\n" );
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document.write( "6x =12\r<BR>\n" );
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document.write( "x=12/6\r<BR>\n" );
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document.write( "x=2\r<BR>\n" );
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document.write( "y=2x+4\r<BR>\n" );
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document.write( "y=2(2)+4\r<BR>\n" );
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document.write( "y=4+4\r<BR>\n" );
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document.write( "y=8\r<BR>\n" );
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document.write( "So x = 2 and y = 8 giving us the ordered pair (2,8) </SPAN>\n" );
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