document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=481630>Question 481630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem... Find the length of the shorter leg of a right triangle if the longer leg is 24 meters and the length of the hypotenuse is 6 meters more than twice the length of the shorter leg.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331187 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24^2 + x^2 = (2x + 6)<BR>\n" );
document.write( "576 + x^2 = 4x^2 +24x +36^2<BR>\n" );
document.write( "0 = 3x^2  +24x  -540 ( we can factor out a 3)<BR>\n" );
document.write( "3(x^2  +8x -180)  = ( x + 18)  ( x - 10)<BR>\n" );
document.write( "Therefore, x = 10.<BR>\n" );
document.write( "c = 26<BR>\n" );
document.write( "24^2  + 10^2  = 26^2<BR>\n" );
document.write( "576 m + 100 m = 16^2 = 676 m<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
document.write( " </SPAN>\n" );
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