document.write( "Question 483854: A train moving at uniform speed takes 20 seconds to pass a cyclist riding at 11 km/hr but only 9 seconds to pass a post. find its length. \n" ); document.write( "
Algebra.Com's Answer #331166 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A train moving at uniform speed takes 20 seconds to pass a cyclist riding at 11 km/hr but only 9 seconds to pass a post. \n" ); document.write( " find it's length. \n" ); document.write( ": \n" ); document.write( "change 11 km/hr to meter/sec \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let L = length of train in meters \n" ); document.write( "Let s = speed of train in m/sec \n" ); document.write( ": \n" ); document.write( "Using the post as ref: \n" ); document.write( "L = 9s is the length of the train in meters \n" ); document.write( ": \n" ); document.write( "Using the bike going 3.056 m/sec, as ref \n" ); document.write( "L = 20(s - 3.056) is the length of the train \n" ); document.write( ": \n" ); document.write( "We can find s: \n" ); document.write( "20(s - 3.056) = 9s \n" ); document.write( "20s - 61.11 = 9s \n" ); document.write( "20s - 9s = 61.11 \n" ); document.write( "11s = 61.11 \n" ); document.write( "s = \n" ); document.write( "s = 5.56 m/sec is the speed of the train \n" ); document.write( "then \n" ); document.write( "9 * 5.56 = 50 meters is the length of the train (post as ref) \n" ); document.write( "and \n" ); document.write( "20(5.56-3.056) ~ 50 meters also using a moving bike as ref \n" ); document.write( " |