document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483871>Question 483871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle ABC is 500m. A=40 degrees and B= 60 degrees. Find the distance AB. Thank You! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331140 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this, we  need to use the law of sins; it states \"The sides of a triangle are to one another in the same ratio as the sines of their opposite angles\".\r<BR>\n" );
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document.write( "So, fist I found the sines of the three angles:<BR>\n" );
document.write( "A =40 degrees = sine is .642<BR>\n" );
document.write( "B = 60 degrees = sine is .86 <BR>\n" );
document.write( "C = 80 degrees = sine is .985\r<BR>\n" );
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document.write( "Next, I added up the three to obtain 2.487.<BR>\n" );
document.write( "So that is the total, to find the proportion of 500 for each side, I multiplied that angles sine/ 2.487 by 500. This resulted in:\r<BR>\n" );
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document.write( "a = 129.1<BR>\n" );
document.write( "b = 172.9<BR>\n" );
document.write( "c = 198.0\r<BR>\n" );
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document.write( "The three sides do total 500.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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