document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49744>Question 49744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> cot 60 degrees<BR>\n" );
document.write( "tan 210 degrees <BR>\n" );
document.write( "sec 210 <BR>\n" );
document.write( "csc 210 <BR>\n" );
document.write( "cot 210 <BR>\n" );
document.write( "cos 11pi/6<BR>\n" );
document.write( "cot 3pi/2<BR>\n" );
document.write( "tan 2pi/3<BR>\n" );
document.write( "csc 5pi/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "please help if anyone can do it i need it by thursday 8/23/06 by 6:30 tomorrow morning please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33105 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cot 60 degrees=1/SQRT(3)<BR>\n" );
document.write( "tan 210 degrees=TAN(180+30)=TAN(30)=1/SQRT(3)<BR>\n" );
document.write( "sec 210=SEC(180+30)=-SEC(30)=-2/SQRT(3)<BR>\n" );
document.write( "csc 210=COSEC(180+30)=-COSEC(30)=-2<BR>\n" );
document.write( "cot 210=COT(180+30)=COT(30)=SQRT(3)<BR>\n" );
document.write( "cos 11pi/6=COS(2PI-PI/6)=COS(PI/6)=SQRT(3)/2<BR>\n" );
document.write( "cot 3pi/2=COT(PI+PI/2)=COT(PI/2)=0<BR>\n" );
document.write( "tan 2pi/3=TAN(PI-PI/3)=-TAN(PI/3)=-SQRT(3)<BR>\n" );
document.write( "csc 5pi/6 =COSEC(PI-PI/6)=COSEC(PI/6)=2 </SPAN>\n" );
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