document.write( "Question 483541: one number is 3 less than a second number. twice the second number is 3 less than 3 times the first. find the two numbers \n" ); document.write( "
Algebra.Com's Answer #330952 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "one number is 3 less than a second number. twice the second number is 3 less than 3 times the first. find the two numbers\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second number is obviously the larger number, and will be named L \n" ); document.write( "The other number will be the smaller and named S\r \n" ); document.write( "\n" ); document.write( "Since the smaller number, or S is 3 less than the larger, then we can say that S = L – 3 ___ S – L = - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, since twice the second number (larger number) is 3 less than 3 times the other number (smaller number), we can say that: 2L = 3S – 3 ______ - 3S + 2L = - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We now have the following simultaneous equations:\r \n" ); document.write( "\n" ); document.write( " S – L = - 3 -------- eq (i) \n" ); document.write( "– 3S + 2L = - 3 ----- eq (ii) \n" ); document.write( " 2S – 2L = - 6 -------- eq (iii) ----- multiplying eq (i) by 2 \n" ); document.write( " – S = - 9 ------ Adding eq (ii) and eq (iii) \n" ); document.write( "S, or smaller number = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting 9 for S in eq (i) gives us: \n" ); document.write( "9 - L = - 3 \n" ); document.write( "- L = - 12\r \n" ); document.write( "\n" ); document.write( "L, or larger number = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------- \n" ); document.write( "Check \n" ); document.write( "----------- \n" ); document.write( "Smaller #: 9 \n" ); document.write( "Larger #: 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Smaller # (9) is 3 less than larger # (12)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Twice larger # (12) = 2(12) = 24 \n" ); document.write( "Thrice smaller # (9) = 3(9) = 27 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Twice larger # (24) is 3 less than thrice smaller # (27)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to MathMadEzy@aol.com \n" ); document.write( " |