document.write( "Question 483541: one number is 3 less than a second number. twice the second number is 3 less than 3 times the first. find the two numbers \n" ); document.write( "

Algebra.Com's Answer #330919 by Maths68(1474) $\"\"$ $\"About$

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Let x and y are two umbers\r
\n" ); document.write( "\n" ); document.write( "One number is 3 less than a second number
\n" ); document.write( "or
\n" ); document.write( "x is 3 less than y
\n" ); document.write( "x=3-y……..(1)\r
\n" ); document.write( "\n" ); document.write( "Twice the second number is 3 less than 3 times the first.
\n" ); document.write( "Or
\n" ); document.write( "2y is 3 less than 3x\r
\n" ); document.write( "\n" ); document.write( "2y=3-3x………(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of x in (2)
\n" ); document.write( "2y=3-3(3-y)
\n" ); document.write( "2y=3-9+3y
\n" ); document.write( "2y=-6+3y
\n" ); document.write( "6=3y-2y
\n" ); document.write( "6=y
\n" ); document.write( "y=6
\n" ); document.write( "Put the value of y in (1)
\n" ); document.write( "x=3-y
\n" ); document.write( "x=3-6
\n" ); document.write( "x=-3
\n" ); document.write( "x,y = -3, 6 \n" ); document.write( "

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