document.write( "Question 483543: the average of 3 numbers is 39. the second is 3 less than twice the first and the third is 6 less than thrice the first. find the 3 numbers. \n" ); document.write( "
Algebra.Com's Answer #330917 by Maths68(1474)\"\" \"About 
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Let first number = x
\n" ); document.write( "The second is 3 less than twice the first= 3-2x
\n" ); document.write( "The third is 6 less than thrice the first= 6-3x\r
\n" ); document.write( "\n" ); document.write( "(first#+second#+third#)/3 = Average
\n" ); document.write( "[(6-3x)+(3-2x)+x]/3=39
\n" ); document.write( "(6-3x+3-2x+x)/3=39
\n" ); document.write( "(9-4x)/3=39 (Multiply by 3 both the sides)
\n" ); document.write( "9-4x=117
\n" ); document.write( "-4x=117-9
\n" ); document.write( "-4x=108
\n" ); document.write( "-4x/4=108/4=4x/4 (Divide by 4 both sides)
\n" ); document.write( "-x=27
\n" ); document.write( "x=-27\r
\n" ); document.write( "\n" ); document.write( "the second is 3 less than twice the first= 3-2x = 3-2(-27)=3+54=57
\n" ); document.write( "third is 6 less than thrice the first= 6-3x=6-3(-27)=6+81=87\r
\n" ); document.write( "\n" ); document.write( "-27,57,87
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