document.write( "Question 482635: What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "
Algebra.Com's Answer #330903 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "** \n" ); document.write( "Compound Interest Formula For Continuous Compounding: A=Pe^rt, P=initial investment, r=annual rate of interest, A=amount after t years. \n" ); document.write( "For given problem:\r \n" ); document.write( "\n" ); document.write( "900=500e^10r \n" ); document.write( "900/500=e^10r=9/5 \n" ); document.write( "take log of both sides \n" ); document.write( "10r*lne=ln (9/5) \n" ); document.write( "log of base=1 \n" ); document.write( "10r=ln(9/5)=.5878 \n" ); document.write( "r=.5878/10=.05878 \n" ); document.write( "ans: \n" ); document.write( "Annual rate of interest compounded continuously needed=5.9% \n" ); document.write( " |