document.write( "Question 482635: What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "
Algebra.Com's Answer #330903 by lwsshak3(11628)\"\" \"About 
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What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years?
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\n" ); document.write( "Compound Interest Formula For Continuous Compounding: A=Pe^rt, P=initial investment, r=annual rate of interest, A=amount after t years.
\n" ); document.write( "For given problem:\r
\n" ); document.write( "\n" ); document.write( "900=500e^10r
\n" ); document.write( "900/500=e^10r=9/5
\n" ); document.write( "take log of both sides
\n" ); document.write( "10r*lne=ln (9/5)
\n" ); document.write( "log of base=1
\n" ); document.write( "10r=ln(9/5)=.5878
\n" ); document.write( "r=.5878/10=.05878
\n" ); document.write( "ans:
\n" ); document.write( "Annual rate of interest compounded continuously needed=5.9%
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