document.write( "Question 49727This question is from textbook
\n" ); document.write( ": x square divided by (x-2)(x-3)=2 divided by (x-2)+ 6 divided by (x-2)(x-3). solve for x. \n" ); document.write( "

Algebra.Com's Answer #33088 by gsmani_iyer(201) $\"\"$ $\"About$

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\n" ); document.write( " $\"x%5E2%2F%28%28x-2%29%28x-3%29%29++=++%282%2F%28x-2%29%29%2B%286%2F%28x-2%29%28x-3%29%29\"$
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\n" ); document.write( " $\"x%5E2%2F%28%28x-2%29%28x-3%29%29\"$ = $\"%282%28x-3%29%2B6%29%2F%28%28x-2%29%28x-3%29%29\"$
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\n" ); document.write( " As both the denominators are same,
\n" ); document.write( " $\"x%5E2+=+2x-6%2B6\"$ . So, $\"x%5E2+=+2x\"$
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\n" ); document.write( " $\"x%5E2-2x+=+0\"$ . $\"x%28x-2%29+=+0\"$
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\n" ); document.write( " So either x or (x-2) = 0.
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\n" ); document.write( " Solution Set = {0, 2} Answer. \n" ); document.write( "

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