document.write( "Question 483424: find the area of an equilateral triangle with altitude 1 unit, leave your answer in simplest radical form. \n" ); document.write( "

Algebra.Com's Answer #330829 by richard1234(7193) $\"\"$ $\"About$

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Two ways to do this:\r
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\n" ); document.write( "\n" ); document.write( "You can draw an altitude and call it h. This splits the equilateral triangle into two 30-60-90 right triangles, each with a leg of 1/2 and the height is sqrt(3)/2. The area is (1/2)(sqrt(3)/2) = sqrt(3)/4.\r
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\n" ); document.write( "\n" ); document.write( "Or, you can say that the area of the triangle is 1*1*(sin 60)/2 = sqrt(3)/4, same result. \n" ); document.write( "

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