document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483360>Question 483360</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question:\r<BR>\n" );
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document.write( "A club consists of 16 men and 19 women. In how many ways can they choose a president, vice president, treasurer, and secretary, along with an advisory committee of six people? \r<BR>\n" );
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document.write( "Comment:<BR>\n" );
document.write( "I think this is a matter of a permutation (the election of the positions) and a combination (the election of the committee), but I don't know how to solve them together. Can you help?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330794 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the gender of each position is irrelevant; you have a total of 35 people.<BR>\n" );
document.write( "You have 4 offices, and 6 committee members, so that's 10 people overall.  So you're combining 35 people, ten at a time, which is:<BR>\n" );
document.write( "35C10=35x34x33x32x31x30x29x28x27x26x25!/10x9x8x7x6x5x4x3x2x25!=183579396<BR>\n" );
document.write( "different arrangements of officers and committee members.. </SPAN>\n" );
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