document.write( "Question 483274: can someone please help me solve the following equations for x
\n" ); document.write( "1) 6/x+3=9x/x^2-9
\n" ); document.write( "2) sqrt2x+3=5
\n" ); document.write( "3) x^3-2x^2-x=2 given x=1 is one solution.
\n" ); document.write( "Thank you
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Algebra.Com's Answer #330770 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
1) We write the equation in the simple way to find the LCD:\r
\n" ); document.write( "\n" ); document.write( "\"6%2F%28x%2B3%29=9x%2F%28x%2B3%29%28x-3%29\".Assuming x different from 3 and -3, multiply both \r
\n" ); document.write( "\n" ); document.write( "sides by (x+3)(x-3) and get:\"6%28x-3%29=9x\"<=>\"3x=-18\"<=>\"x=-6\".\r
\n" ); document.write( "\n" ); document.write( "2)\"sqrt%282x%2B3%29=5\" Squaring both sides we get:2x+3=25<=>2x=22<=>x=11.\r
\n" ); document.write( "\n" ); document.write( "3)Since x=1 is a solution the polynomial \"x%5E3-2x%5E2-x-2\" is divisible by x-1\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E3-2x%5E2-x-2%29%2F%28x-1%29=x%5E2-x-2\"<=>\"x%5E3-2x%5E2-x-2=%28x-1%29%28x%5E2-x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "To find the other roots we solve the quadratic equation:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-2=0\"<=>\"%28x-2%29%28x%2B1%29=0\". The solution set for the original equation \r
\n" ); document.write( "\n" ); document.write( "is:{-1, 1, 2}.
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