document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483275>Question 483275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company manufactures three types of t.vs A,B and C. The company manufactures four less type B than twice A, and one more type B than the sum of types A and type C. If the total number of t.vs manufactured per week is 51. How many of each type of t.v are manufactured.<BR>\n" );
document.write( "Can someone please help this question has me in a twist! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330766 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let type A be x \r<BR>\n" );
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document.write( "Then type B = 2x+4<BR>\n" );
document.write( "And B-1 = x+C<BR>\n" );
document.write( "Substituting for B <BR>\n" );
document.write( "2x+4-1 = x+C<BR>\n" );
document.write( " So C = x+3\r<BR>\n" );
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document.write( "Given that total number of tvs manufactured per week is 51 which is A+B+C<BR>\n" );
document.write( "so<BR>\n" );
document.write( "x+ (2x+4) + (x+3) = 51<BR>\n" );
document.write( "4x+7 = 51<BR>\n" );
document.write( "4x = 44 so x =11<BR>\n" );
document.write( "Type B = 2x+4 = 2*11+4 = 26<BR>\n" );
document.write( "and C = x+3 = 11+3 = 14\r<BR>\n" );
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document.write( "Ans Type A= 11, Type B = 26 & type C = 14 </SPAN>\n" );
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