document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483292>Question 483292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When a ball is thrown upward at a speed of 19 m/s, its height s above the ground (in meters) after t seconds is given by the formula\r<BR>\n" );
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document.write( "s=19t-4.9t^2<BR>\n" );
document.write( "Find the height of the ball after 3 seconds </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330759 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Height of the ball after 3 seconds is achieved by substituting t=3 in below formula<BR>\n" );
document.write( "s=19t-4.9t^2\r<BR>\n" );
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document.write( "s=19*3-4.9*3^2<BR>\n" );
document.write( "s= 57 - 4.9*9<BR>\n" );
document.write( "s= 57- 44.1<BR>\n" );
document.write( "s= 12.9 m <BR>\n" );
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