document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483296>Question 483296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello Tutors of Algebra.com,\r<BR>\n" );
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document.write( "I don't if is the right section but here goes\r<BR>\n" );
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document.write( "A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of solution that is 48% alcohol . How much of each available solution should he use ?\r<BR>\n" );
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document.write( "thanks in advance :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330754 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of solution that is 48% alcohol . How much of each available solution should he use ? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
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document.write( "0.40x + 0.60(100-x) = 0.48*100<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40x + 60*100 - 60x = 48*100<BR>\n" );
document.write( "-20x = -12*100<BR>\n" );
document.write( "x = 60 mL (amt. of 40% solution needed)<BR>\n" );
document.write( "100-x = 40mL (amt. of 60% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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