document.write( "Question 483278: Find four numbers in GP whose sum is 85 and their product is 4096 \n" ); document.write( "
Algebra.Com's Answer #330750 by mathstutor494(120)\"\" \"About 
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Let the 4 numbers in GP be
\n" ); document.write( "a/r, a, ar, ar^2\r
\n" ); document.write( "\n" ); document.write( "Given that sum is 85 and their product is 4096. \r
\n" ); document.write( "\n" ); document.write( "Accordingly....
\n" ); document.write( "a/r+a+ar+ar^2=85 & a/r*a*ar*ar^2=4096
\n" ); document.write( "a/r(1+r+r^2+r^3)=85 & a^4r^2 = 4096 \r
\n" ); document.write( "\n" ); document.write( "Since a^4r^2 = 4096 so a^4= 4096/r^2 = 8^4/r^2
\n" ); document.write( "So a = 8/sqrt(r)\r
\n" ); document.write( "\n" ); document.write( "Substituting value of a in sum equation leads to ...
\n" ); document.write( "(8/sqrt(r)r)(1+r+r^2+r^3)=85
\n" ); document.write( "(1+r+r^2+r^3)/(sqrt(r)r)= 85/8
\n" ); document.write( "Therefore
\n" ); document.write( "(1+r+r^2+r^3)= 85 and sqrt(r)r = 8
\n" ); document.write( "Solving 2nd eqn
\n" ); document.write( "r*r^(1/2)= 2^(3/2)
\n" ); document.write( "r^(3/2)= 4^(3/2)
\n" ); document.write( "so r = 4\r
\n" ); document.write( "\n" ); document.write( "Substituting value of r in below eqn and solving for a
\n" ); document.write( "a^4r^2 = 4096
\n" ); document.write( "(a^4)(4^2)=4096
\n" ); document.write( "(a^4)*16= 4096
\n" ); document.write( "(a^4)= 4096/16 = 256 = 4^4
\n" ); document.write( "So a = 4\r
\n" ); document.write( "\n" ); document.write( "Since four numbers in GP are...a/r, a, ar, ar^2
\n" ); document.write( "Therefore four numbers in GP are...
\n" ); document.write( "4/4, 4, 4*4, 4*4^2
\n" ); document.write( "1, 4, 16, 64\r
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