document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483262>Question 483262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many numbers between 4000 an 5000 can be formed with the digit 2,3,4,5,6,7? How many of these numbers are divisible by 5?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330743 by </B><A HREF=/tutors/aboutme.mpl?userid=mathstutor494><B>mathstutor494(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathstutor494><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathstutor494><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Numbers between 4000 an 5000  would start with 4 and will have 4 digits.\r<BR>\n" );
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document.write( "So the first position will be filled by 4 and the number would look like\r<BR>\n" );
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document.write( "4 _ _ _\r<BR>\n" );
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document.write( "Then the remaining 3 digits will be formed from remaining 5 digit 2,3,5,6,7 in 5P3 ways (no repeatitions).\r<BR>\n" );
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document.write( "Numbers formed = 1. 5P3 <BR>\n" );
document.write( "= 5!/(5-3)!<BR>\n" );
document.write( "= 5*4*3<BR>\n" );
document.write( "= 60\r<BR>\n" );
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document.write( "In order for these numbers to be divisible by 5, the number would be <BR>\n" );
document.write( "4 - - 5\r<BR>\n" );
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document.write( "And the number would be formed by filling up 2nd and 3rd digit from the remaining 4 digits 2,3,6,7 in 4P2 ways i.e 4*3 = 12 <BR>\n" );
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