document.write( "Question 483256: write the equation in point slope form for a line that passes through(-4,6) and is perpendicular to the line 2x+3y=12 \n" ); document.write( "

Algebra.Com's Answer #330736 by mananth(16946) $\"\"$ $\"About$

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2 x + 3 y = 12
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "3 y = -2 x + 12
\n" ); document.write( "Divide by 3
\n" ); document.write( " y = - 2/3 x + 4
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -2/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 3/2
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 3/2
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\n" ); document.write( "m= 3/2 ,point ( -4 , 6 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "6 = -6.00 + b
\n" ); document.write( "b= 12
\n" ); document.write( "m= 1 1/2
\n" ); document.write( "The required equation is y =3/ 2x+12
\n" ); document.write( "m.ananth@hotmail.ca
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