document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482896>Question 482896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is one less than three times the smaller. if their sum is 63. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330722 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y are two numbers\r<BR>\n" );
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document.write( "y=3x-1<BR>\n" );
document.write( "x+y=63<BR>\n" );
document.write( "x+3x-1=63 (Putting the value of ‘y’)<BR>\n" );
document.write( "4x=63+1<BR>\n" );
document.write( "4x=64<BR>\n" );
document.write( "4x/4=64/4 (Divide by 4 both sides)<BR>\n" );
document.write( "x=16\r<BR>\n" );
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document.write( "x+y=63 (Putting the value of ’x’)<BR>\n" );
document.write( "16+y=63<BR>\n" );
document.write( "y=63-16\r<BR>\n" );
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document.write( "y=47\r<BR>\n" );
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document.write( "Numbers are 16 and 47.<BR>\n" );
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