document.write( "Question 483212: when we placed a boy 4 feet from the fulcrum, and a girl 12 feet from the fulcrum on the side of the teeter board, they balance a man weighing 150 pounds who is seated 6 feet from the fulcrum on the other side. also, the board is balanced if the boy moves to 8 feet and the girl to 6 feet from the fulcrum on their side. Find their weights \n" ); document.write( "

Algebra.Com's Answer #330721 by mananth(16946) $\"\"$ $\"About$

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let weight of boy be x --- 4 feet from fulcrum
\n" ); document.write( "weight of girl be y ---12 feet from fulcrum\r
\n" ); document.write( "\n" ); document.write( "balances 150*6
\n" ); document.write( "4x+12y=150*6..........1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Similarly
\n" ); document.write( "8x+6y= 150*6.........2\r
\n" ); document.write( "\n" ); document.write( "multiply (1) by -2
\n" ); document.write( "we get
\n" ); document.write( "-8x-24y=-1800
\n" ); document.write( "add this to (2)
\n" ); document.write( "-18y=-900
\n" ); document.write( "y=50 pounds weight of girl
\n" ); document.write( "plug value of y in (2)\r
\n" ); document.write( "\n" ); document.write( "8x+300=900
\n" ); document.write( "8x=600
\n" ); document.write( "x=75 pounds weight of boy\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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