document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483205>Question 483205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Frankie has 22 coins in pocket worth a total of $4.75. If Frankie only has dimes and quarters in his pocket, how many of each does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330719 by </B><A HREF=/tutors/aboutme.mpl?userid=gabriel24><B>gabriel24(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gabriel24><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gabriel24><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = no. of dimes (1 dime = 10 cents)<BR>\n" );
document.write( "    y = no. of quarters (1 quarter = 25 cents)\r<BR>\n" );
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document.write( "x + y = 22 coins<BR>\n" );
document.write( "x = 22 - y      (eq. 1)\r<BR>\n" );
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document.write( "0.1x + 0.25y = 4.75  (eq. 2)\r<BR>\n" );
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document.write( "SUBSTITUTE eq. 1 to eq. 2<BR>\n" );
document.write( "0.1(22 - y) + 0.25y = 4.75<BR>\n" );
document.write( "2.2 - 0.1y + 0.25y = 4.75<BR>\n" );
document.write( "-0.1y + 0.25y = 4.75 - 2.2<BR>\n" );
document.write( "0.15y = 2.55<BR>\n" );
document.write( "y = 17 total number of quarters\r<BR>\n" );
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document.write( "x = 22 - y<BR>\n" );
document.write( "x = 22 - 17<BR>\n" );
document.write( "x = 5 total number of dimes<BR>\n" );
document.write( " </SPAN>\n" );
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