document.write( "Question 483009: A says to B \"my present age is five times of your age when i was as old as you are now.\" The sum of their ages is 48 years. Find their age. \n" ); document.write( "
Algebra.Com's Answer #330657 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A says to B \"my present age is five times of your age when i was as old as you are now.\" \n" ); document.write( "A = 5B \n" ); document.write( ": \n" ); document.write( " The sum of their ages is 48 years. \n" ); document.write( "A + B = 48 \n" ); document.write( "B = (48-A) \n" ); document.write( "Replace B with (48-A) in the 1st equation \n" ); document.write( "A = 5(48-A) \n" ); document.write( "A = 240 - 5A \n" ); document.write( "A + 5A = 240 \n" ); document.write( "6A = 240 \n" ); document.write( " A = \n" ); document.write( " A = 40 yrs old \n" ); document.write( "and \n" ); document.write( "B = 48-40 \n" ); document.write( "B = 8 yrs old \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |